Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 442: 60

Answer

$r=20\sqrt 2$ $x=20$

Work Step by Step

$sin~θ=\frac{opp}{hyp}$ $sin~45°=\frac{20}{r}$ $\frac{\sqrt 2}{2}=\frac{20}{r}$ $r=\frac{20}{\frac{\sqrt 2}{2}}=20\frac{2}{\sqrt 2}=\frac{40}{\sqrt 2}\frac{\sqrt 2}{\sqrt 2}=\frac{40\sqrt 2}{2}=20\sqrt 2$ $tan~θ=\frac{opp}{adj}$ $tan~45°=\frac{20}{x}$ $1=\frac{20}{x}$ $x=20$
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