## Algebra and Trigonometry 10th Edition

(a) $θ=60°=\frac{\pi}{3}rad$ (b) $θ=45°=\frac{\pi}{4}rad$
Consult the table on page 436: (a) $csc~θ=\frac{2\sqrt 3}{3}$ $\frac{1}{sin~θ}=\frac{2\sqrt 3}{3}$ $sin~θ=\frac{3}{2\sqrt 3}=\frac{3}{2\sqrt 3}\frac{\sqrt 3}{\sqrt 3}=\frac{3\sqrt 3}{2(3)}=\frac{\sqrt 3}{2}$ $θ=60°=\frac{\pi}{3}rad$ (b) $θ=45°=\frac{\pi}{4}rad$