Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 442: 58

Answer

$r=60$ $x=30\sqrt 3$

Work Step by Step

$sin~θ=\frac{opp}{hyp}$ $sin~30°=\frac{30}{r}$ $\frac{1}{2}=\frac{30}{r}$ $r=30(2)=60$ $tan~θ=\frac{opp}{adj}$ $tan~30°=\frac{30}{x}$ $\frac{\sqrt 3}{3}=\frac{30}{x}$ $x=\frac{30}{\frac{\sqrt 3}{3}}=30\frac{3}{\sqrt 3}=\frac{90}{\sqrt 3}\frac{\sqrt 3}{\sqrt 3}=\frac{90\sqrt 3}{3}=30\sqrt 3$
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