Answer
(a) $θ=60°=\frac{\pi}{3}rad$
(b) $θ=45°=\frac{\pi}{4}rad$
Work Step by Step
Consult the table on page 436:
(a) $cot~θ=\frac{\sqrt 3}{3}$
$\frac{1}{tan~θ}=\frac{\sqrt 3}{3}$
$tan~θ=\frac{3}{\sqrt 3}=\frac{3}{\sqrt 3}\frac{\sqrt 3}{\sqrt 3}=\frac{3\sqrt 3}{3}=\sqrt 3$
$θ=60°=\frac{\pi}{3}rad$
(b) $sec~θ=\sqrt 2$
$\frac{1}{cos~θ}=\sqrt 2$
$cos~θ=\frac{1}{\sqrt 2}=\frac{1}{\sqrt 2}\frac{\sqrt 2}{\sqrt 2}=\frac{\sqrt 2}{2}$
$θ=45°=\frac{\pi}{4}rad$
