The identity is verified. $(sec~θ+tan~θ)(sec~θ-tan~θ)=1$
Work Step by Step
Use: $1+tan^2θ=sec^2θ$ $1=sec^2θ-tan^2θ$ $(sec~θ+tan~θ)(sec~θ-tan~θ)=sec^2θ-tan^2θ=1$
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