The identity is verified. $sin^2θ-cos^2θ=2sin^2θ-1$
Work Step by Step
Use: $sin^2θ+cos^2θ=1$ $sin^2θ-1=-cos^2θ$ $sin^2θ-cos^2θ=sin^2θ+sin^2θ-1=2sin^2θ-1$
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