Answer
The identity is verified.
$sin^2θ-cos^2θ=2sin^2θ-1$
Work Step by Step
Use:
$sin^2θ+cos^2θ=1$
$sin^2θ-1=-cos^2θ$
$sin^2θ-cos^2θ=sin^2θ+sin^2θ-1=2sin^2θ-1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 442: 48
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