Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 442: 40


(a) $sec~\beta=\frac{4\sqrt 7}{7}$ (b) $sin~\theta=\frac{3}{4}$ (c) $cot~\beta=\frac{\sqrt 7}{3}$ (d) $sin(90°-\beta)=\frac{\sqrt 7}{4}$

Work Step by Step

(a) $sec~\beta=\frac{1}{cos~\beta}=\frac{1}{\frac{\sqrt 7}{4}}=\frac{4}{\sqrt 7}=\frac{4\sqrt 7}{7}$ (b) $sin^2\beta+cos^2\beta=1$ $sin^2\beta=1-(\frac{\sqrt 7}{4})^2=\frac{9}{16}$ $sin~\theta=\frac{3}{4}$ (c) $cot~\beta=\frac{cos~\beta}{sin~\beta}=\frac{\frac{\sqrt 7}{4}}{\frac{3}{4}}=\frac{\sqrt 7}{3}$ (d) $sin(90°-\beta)=cos~\beta=\frac{\sqrt 7}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.