Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.2 - Polynomial Functions of Higher Degree - 3.2 Exercises - Page 261: 66



Work Step by Step

One of the zeroes must be a repeated zero so that we can find a polynomial of degree 3. Let's make $x=6$ a repeated zero: $f(x)=a[x-(-2)](x-6)^2=a(x+2)(x^2-12x+36)=a(x^3-10x^2+12x+72)$ $a$ can be any value. If $a=1$: $f(x)=x^3-10x^2+12x+72$
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