Work Step by Step
$f(x)=a[x-(4+\sqrt 3)][x-(4-\sqrt 3)]=a[(x-4)-\sqrt 3][(x-4)+\sqrt 3]=a[(x-4)^2-(\sqrt 3)^2]=a(x^2-8x+16-3)=a(x^2-8x+13)$ $a$ can be any value. If $a=1$: $f(x)=x^2-8x+13$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.