## Algebra and Trigonometry 10th Edition

$f(x)=(x+3)^2$
$x=-3$ must be a repeated zero so that we can find a polynomial of degree 2: $f(x)=a[x-(-3)]^2=a(x+3)^2$ $a$ can be any value. If $a=1$: $f(x)=(x+3)^2$