## Algebra and Trigonometry 10th Edition

$f(x)=x^3+4x^2-5x$
$f(x)=a[x-(-5)](x-0)(x-1)=a(x+5)x(x-1)=a(x^3+4x^2-5x)$ $a$ can be any value. If $a=1$: $f(x)=x^3+4x^2-5x$