Work Step by Step
$f(x)=a[x-(1+\sqrt 2)][x-(1-\sqrt 2)]=a[(x-1)-\sqrt 2][(x-1)+\sqrt 2]=a[(x-1)^2-(\sqrt 2)^2]=a(x^2-2x+1-2)=a(x^2-2x-1)$ $a$ can be any value. If $a=1$: $f(x)=x^2-2x+1-2=x^2-2x-1$
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