Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 36


$f(x)=\frac{1}{x}$ $g(x)=x+10$

Work Step by Step

$h(x)=\frac{1}{x+10}$ Let $g(x)=x+10$ and $f(x)=\frac{1}{x}$. Then $(f \circ g)(x)=\frac{1}{g(x)}=\frac{1}{x+10}=h(x)$.
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