## Algebra: A Combined Approach (4th Edition)

$f(x)=\frac{1}{x}$ $g(x)=x+10$
$h(x)=\frac{1}{x+10}$ Let $g(x)=x+10$ and $f(x)=\frac{1}{x}$. Then $(f \circ g)(x)=\frac{1}{g(x)}=\frac{1}{x+10}=h(x)$.