Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set: 31

Answer

$f(x)=x^2$ $g(x)=x+2$

Work Step by Step

$h(x)=(x+2)^2$. Let $f(x)=x^2$ and $g(x)=x+2$. Then $(f \circ g)(x)=(x+2)^2=h(x)$.
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