Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set: 26

Answer

$G(x)=\sqrt {3x}=(g \circ f)(x)$

Work Step by Step

$f(x)=3x$ $g(x)=\sqrt x$ $G(x)=\sqrt {3x}$. So $G(x)=\sqrt {f(x)}=g(f(x))=(g \circ f)(x)$.
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