Answer
$H(x)=\sqrt {x^2+2}=(g \circ h)(x)$
Work Step by Step
$h(x)=x^2+2$
$g(x)=\sqrt x$
$H(x)=\sqrt {x^2+2}$. So
$H(x)=\sqrt {h(x)}=g(h(x))=(g \circ h)(x)$.
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