Answer
$f(x)=\frac{1}{x}$
$g(x)=2x-3$
Work Step by Step
$h(x)=\frac{1}{2x-3}$
Let
$g(x)=2x-3$ and
$f(x)=\frac{1}{x}$. Then
$(f \circ g)(x)=\frac{1}{g(x)}=\frac{1}{2x-3}=h(x)$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 35
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