Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 34


$f(x)=x^2+3$ $g(x)=3x+4$

Work Step by Step

$h(x)=(3x+4)^2+3$ Let $g(x)=3x+4$ and $f(x)=x^2+3$. Then $(f \circ g)(x)=(g(x))^2+3 = (3x+4)^2 + 3$.
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