Answer
$(f\circ g)(x)=7\sqrt[3]{x}-1$
$(g\circ f)(x)=\sqrt[3]{7x-1}$
Work Step by Step
$f(x)=7x-1$ $;$ $g(x)=\sqrt[3]{x}$
$(f\circ g)(x)$
To find $(f\circ g)(x)$, substitute $x$ by $g(x)$ in $f(x)$ and simplify if possible:
$(f\circ g)(x)=f(g(x))=7\sqrt[3]{x}-1$
$(g\circ f)(x)$
To find $(g\circ f)(x)$, substitute $x$ by $f(x)$ in $g(x)$ and simplify if possible:
$(g\circ f)(x)=g(f(x))=\sqrt[3]{7x-1}$