Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 27


$F(x)=9x^2+2=(h \circ f)(x)$

Work Step by Step

$f(x)=3x$ $h(x)=x^2+2$ $F(x)=9x^2+2$ $F(x)=(3x)^2+2$. So $F(x)=(f(x))^2+2=h(f(x))=(h \circ f)(x)$.
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