Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 33

Answer

$f(x)=\sqrt x +2$ $g(x)=x+5$

Work Step by Step

$h(x)=\sqrt {x+5} + 2$ Let $g(x)=x+5$ and $f(x)=\sqrt x +2$. Then $(f \circ g)(x)=\sqrt {g(x)} + 2 = \sqrt {x+5} + 2 = h(x)$
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