Answer
$\dfrac{9y}{\sqrt[4]{4y^{9}}}=\dfrac{9\sqrt[4]{4y^{3}}}{2y^{2}}$
Work Step by Step
$\dfrac{9y}{\sqrt[4]{4y^{9}}}$
Simplify the expression:
$\dfrac{9y}{\sqrt[4]{4y^{9}}}=\dfrac{9y}{y^{2}\sqrt[4]{4y}}=\dfrac{9}{y\sqrt[4]{4y}}=...$
Multiply the fraction by $\dfrac{\sqrt[4]{4y^{3}}}{\sqrt[4]{4y^{3}}}$ and simplify:
$...=\dfrac{9}{y\sqrt[4]{4y}}\cdot\dfrac{\sqrt[4]{4y^{3}}}{\sqrt[4]{4y^{3}}}=\dfrac{9\sqrt[4]{4y^{3}}}{y\sqrt[4]{16y^{4}}}=\dfrac{9\sqrt[4]{4y^{3}}}{y(2y)}=\dfrac{9\sqrt[4]{4y^{3}}}{2y^{2}}$
