Answer
$\dfrac{3}{\sqrt[3]{2}}=\dfrac{3\sqrt[3]{4}}{2}$
Work Step by Step
$\dfrac{3}{\sqrt[3]{2}}$
Multiply the fraction by $\dfrac{\sqrt[3]{4}}{\sqrt[3]{4}}$ and simplify:
$\dfrac{3}{\sqrt[3]{2}}=\dfrac{3}{\sqrt[3]{2}}\cdot\dfrac{\sqrt[3]{4}}{\sqrt[3]{4}}=\dfrac{3\sqrt[3]{4}}{\sqrt[3]{8}}=\dfrac{3\sqrt[3]{4}}{2}$