Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises - Page 496: 49


$9w^{4} - z^{4}$

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ In the given formula let $3w^{2}$ represents a and $z^{2}$ represents b. $(3w^{2}-z^{2}) (3w^{2}+z^{2}) = (3w^{2})^{2} - (z^{2})^{2}$ = $9w^{4} - z^{4}$
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