## Algebra 1

$(9k+2q)^{2}$=$81k^{2}$+36kq+$4q^{2}$
To simplify the product $(9k+2q)^{2}$ we'll apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$ and set a=9k and b=2q Therefore, $(9k+2q)^{2}$ =$(9k)^{2}$+2(9k)(2q)+$(2q)^{2}$ =$81k^{2}$+36kq+$4q^{2}$