Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises: 38

Answer

$(4s-t)^{2}$=$16s^{2}$-8st+$t^{2}$

Work Step by Step

To simplify the product $(4s-t)^{2}$ we'll apply the rule that states that $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ and set a=4s and b=t Therefore, $(4s-t)^{2}$ =$(4s)^{2}$-2(4s)(t)+$(t)^{2}$ =$16s^{2}$-8st+$t^{2}$
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