## Algebra 1

$(4s-t)^{2}$=$16s^{2}$-8st+$t^{2}$
To simplify the product $(4s-t)^{2}$ we'll apply the rule that states that $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ and set a=4s and b=t Therefore, $(4s-t)^{2}$ =$(4s)^{2}$-2(4s)(t)+$(t)^{2}$ =$16s^{2}$-8st+$t^{2}$