## Algebra 1

$(8r-5s)^{2}$=$64r^{2}$-80rs+$25s^{2}$
To simplify the product $(8r-5s)^{2}$ we'll apply the rule that states that $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ and set a=8r and b=5s Therefore, $(8r-5s)^{2}$ =$(8r)^{2}$-2(8r)(5s)+$(5s)^{2}$ =$64r^{2}$-80rs+$25s^{2}$