Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises: 41

Answer

$(8r-5s)^{2}$=$64r^{2}$-80rs+$25s^{2}$

Work Step by Step

To simplify the product $(8r-5s)^{2}$ we'll apply the rule that states that $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ and set a=8r and b=5s Therefore, $(8r-5s)^{2}$ =$(8r)^{2}$-2(8r)(5s)+$(5s)^{2}$ =$64r^{2}$-80rs+$25s^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.