## Algebra 1

$(2a+b)^{2}$=$4a^{2}$+4ab+$b^{2}$
To simplify the product $(2a+b)^{2}$ we'll apply the rule that states that $(x+y)^{2}$=$x^{2}$+2xy+$y^{2}$ and set x=2a and y=b Therefore, $(2a+b)^{2}$ =$(2a)^{2}$+2(2a)(b)+$b^{2}$ =$4a^{2}$+4ab+$b^{2}$