Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises - Page 496: 39

Answer

$(g-7h)^{2}$=$g^{2}$-14gh+$49h^{2}$

Work Step by Step

To simplify the product $(g-7h)^{2}$ we'll apply the rule that states that $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ and set a=g and b=7h Therefore, $(g-7h)^{2}$ =$g^{2}$-2(g)(7h)+$(7h)^{2}$ =$g^{2}$-14gh+$49h^{2}$
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