Algebra 1

$(m+3n)^{2}$=$m^{2}$+6mn+$9n^{2}$
To simplify the product $(m+3n)^{2}$ we'll apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$ and set a=m and b=3n Therefore, $(m+3n)^{2}$ =$m^{2}$+2(m)(3n)+$(3n)^{2}$ =$m^{2}$+6mn+$9n^{2}$