Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises - Page 496: 48


$4p^{4} - 49q^{2}$

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ In the given formula let $2p^{2}$ represents a and 7q represents b. $(2p^{2}-7q) (2p^{2}+7q) = (2p^{2})^{2} - (7q)^{2}$ = $4p^{4} - 49q^{2}$
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