Answer
No, they are not equivalent.
Work Step by Step
$(x^2)^3 = x^2 * x^2 * x^2 = x^6$
$x^{2^3}= x ^{2*2*2} = x^8$
$x^6 \ne x^8$ (for any value other than 1 or 0)
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 66
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