Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises: 23

Answer

$\frac{1}{49a^2}$

Work Step by Step

We start with the given expression: $(7a)^{-2}$ The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression: $\frac{1}{(7a)^2}$ To raise a product to a power, we raise each factor to the power and multiply: $\frac{1}{7^2a^2}$ We expand the constant power: $\frac{1}{7\times7a^2}=\frac{1}{49a^2}$
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