Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 34



Work Step by Step

The given expression : $(3b^{-2})^{2}(a^{2}b^{4})^{3}$ Now, $(ab)^{n} = a^{n}b^{n}$ Hence, $(3b^{-2})^{2}$ = $9$ X $b^{-4}$ and $(a^{2}b^{4})^{3}$ = $a^{6}$ X $b^{12}$ Thus,the expression becomes : $9$ X $b^{-4}$ X $a^{6}$ X $b^{12}$ This becomes : $9$ X $b^{-4+12}$ X $a^{6}$ Final result : $9a^{6}b^{8}$
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