## Algebra 1

$1.3312053 \times 10^{25}$
RECALL: (i) $(ab)^m=a^mb^m$ (ii) $(a^m)^n=a^{mn}$ (iii) $a^{-m} = \dfrac{1}{a^m} a\ne0$ Use the rules above to obtain: $=2.37^{3} \times (10^{8})^{3} \\=13.312053 \times 10^{8\cdot 3} \\=(1.3312053 \cdot 10) \times 10^{24} \\=1.3312053 \times 10^{1+24} \\=1.3312053 \times 10^{25}$