Answer
$\frac{d^{8}}{c^{18}}$
Work Step by Step
The given expression : $c^{-12}(c^{-2}d)^{3}d^{5}$
Now, $(ab)^{n} = a^{n}b^{n}$
Hence, $(c^{-2}d)^{3}$ = $c^{-6}$ X $d^{3}$
Thus,the expression becomes : $c^{-12}$ X $c^{-6}$ X $d^{3}$ X $d^{5}$
This becomes : $c^{-12-6}$ X $d^{3+5}$
Final result : $c^{-18}d^{8}=\frac{d^{8}}{c^{18}}$ (since $a^{-n}=\frac{1}{a^{n}}$)
