Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 35



Work Step by Step

The given expression : $c^{-12}(c^{-2}d)^{3}d^{5}$ Now, $(ab)^{n} = a^{n}b^{n}$ Hence, $(c^{-2}d)^{3}$ = $c^{-6}$ X $d^{3}$ Thus,the expression becomes : $c^{-12}$ X $c^{-6}$ X $d^{3}$ X $d^{5}$ This becomes : $c^{-12-6}$ X $d^{3+5}$ Final result : $c^{-18}d^{8}=\frac{d^{8}}{c^{18}}$ (since $a^{-n}=\frac{1}{a^{n}}$)
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