## Algebra 1

$8$ $times$ $larger$
Let the volume of the one with the smaller side be $V1$ Let the volume of the one with the bigger side be $V2$ Hence, $V1=(3x)^{3}=3^{3}$ X $x^{3}$ and $V2=(6x)^{3}=6^{3}$ X $x^{3}$ Thus, Ratio of $V2$ to $V1$ = $\frac{6^{3}}{3^{3}}=\frac{216}{27}=8$ Therefore, Final result : The one with the side $6x$ is $8$ times larger.