Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises: 59

Answer

$b^{17}$

Work Step by Step

RECALL: (i) $(a^m)^n = a^{mn}$ (ii) $(ab)^m=a^mb^m$ (ii) $a^m \cdot a^n =a^{m+n}$ (iv) $a^0=1, a\ne0$ Use rule (i) above to obtain: $=b^{5\cdot3}b^2 \\=b^{15}b^2$ Use rule (iii) above to obtain: $=b^{15+2} \\=b^{17}$
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