Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 52



Work Step by Step

$7(c^{1})^{?}=7c^{8}$ Since $7$ is a factor on both sides of the equation, it plays no role in the equation. If we were solving it, we would divide by $7$ and it would cancel on both sides. To raise a power to a power, we multiply the exponents. Therefore, in order for this equation to be correct, the product of $1$ and the second exponent must equal $8$. The only way this would work is if the second exponent is $8$, because $1\times8=8$. Therefore the correct equation is $7(c^{1})^{8}=7c^{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.