Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 33

Answer

$-5-2\sqrt{5}$

Work Step by Step

Multiply using the conjugate. Remember that $(a^2-b^2)$ is $(a+b)(a-b)$ $\frac{\sqrt{5}}{2-\sqrt{5}}\cdot \frac{2+\sqrt{5}}{2+\sqrt{5}}=\frac{2\sqrt{5}+5}{4-5}=\frac{2\sqrt{5}+5}{-1}=-5-2\sqrt{5}$
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