Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 616: 29

Answer

$62-20\sqrt{6}$

Work Step by Step

Multiply using FOIL. $(5\sqrt{2}-2\sqrt{3})^2=(5\sqrt{2})^2+2(-10\sqrt{2}\sqrt{3})+(-2\sqrt{3})^2 =25\cdot 2-20\sqrt{6}+4\cdot 3 =50-20\sqrt{6}+12 =62-20\sqrt{6}$
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