Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 19

Answer

$9\frac{1}{2}\sqrt5$

Work Step by Step

$-\frac{1}{2}\sqrt5+2\sqrt{125}\longrightarrow$ factor the perfect square out of 125 =$-\frac{1}{2}\sqrt5+2\sqrt{25\times5}\longrightarrow$ multiplication property of square roots =$-\frac{1}{2}\sqrt5+2(\sqrt{25})(\sqrt5)\longrightarrow$ simplify =$-\frac{1}{2}\sqrt5+2(5)(\sqrt5)\longrightarrow$ multiply =$-\frac{1}{2}\sqrt5+10\sqrt5\longrightarrow$ use distributive property =$\sqrt5(-\frac{1}{2}+10)\longrightarrow$ simplify =$9\frac{1}{2}\sqrt5$
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