Answer
$-8\sqrt{3}+12$
Work Step by Step
$-\sqrt{12}(4-2\sqrt{3})=-4\sqrt{12}+2\sqrt{12}\cdot \sqrt{3}=-4 (\sqrt{4}\cdot \sqrt{3})+2\sqrt{36}=-4(2\cdot \sqrt{3})+2\cdot 6=-8\sqrt{3}+12$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 616: 24
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