Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 17

Answer

$9\sqrt{10}$

Work Step by Step

$-6\sqrt{10}+5\sqrt{90}\longrightarrow$ factor the perfect square out of 90 =$-6\sqrt{10}+5\sqrt{9\times10}\longrightarrow$ multiplication property of square roots =$-6\sqrt{10}+5(\sqrt{9})(\sqrt{10})\longrightarrow$ simplify =$-6\sqrt{10}+5(3)(\sqrt{10})\longrightarrow$ multiply =$-6\sqrt{10}+15\sqrt{10}\longrightarrow$ use distributive property =$\sqrt{10}(-6+15)\longrightarrow$ simplify =$9\sqrt{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.