Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 26

Answer

$106+6\sqrt{77}$

Work Step by Step

$(3\sqrt{11}+\sqrt{7})^2=3\sqrt{11}(3\sqrt{11}+\sqrt{7})+\sqrt{7}(3\sqrt{11}+\sqrt{7})=9\sqrt{121}+3\sqrt{77}+3\sqrt{77}+\sqrt{49}=9\sqrt{121}+6\sqrt{77}+\sqrt{49}=99+7+6\sqrt{77}=106+6\sqrt{77}$
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