Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 28

Answer

$-\sqrt{6}$

Work Step by Step

Multiply using $FOIL$. $(\sqrt{6}+\sqrt{3})(\sqrt{2}-2)=\sqrt{6}\cdot \sqrt{2}-2\sqrt{6}+\sqrt{3}\cdot \sqrt{2}-2\sqrt{3}=\sqrt{12}-2\sqrt{6}+\sqrt{6}-2\sqrt{3}=\sqrt{12}-\sqrt{6}-2\sqrt{3}=2\sqrt{3}-\sqrt{6}-2\sqrt{3}=-\sqrt{6}$
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