Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 616: 15

Answer

$-7\sqrt5$

Work Step by Step

$3\sqrt{45}-8\sqrt{20}\longrightarrow$ factor the perfect squares out of 45 and 20 =$3\sqrt{9\times5}-8\sqrt{4\times5}\longrightarrow$ multiplication property of square roots =$3(\sqrt{9})(\sqrt5)-8(\sqrt{4})(\sqrt5)\longrightarrow$ simplify =$3(3)(\sqrt5)-8(2)(\sqrt5)\longrightarrow$ multiply =$9\sqrt5-16\sqrt5\longrightarrow$ use distributive property =$\sqrt5(9-16)\longrightarrow$ simplify =$-7\sqrt5$
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