## Algebra 1

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 21

#### Answer

$2\sqrt3+3\sqrt2$

#### Work Step by Step

$\sqrt6(\sqrt2+\sqrt3)\longrightarrow$ use the distributive property =$(\sqrt6)(\sqrt2)+(\sqrt6)(\sqrt3)\longrightarrow$ multiplication property of square roots =$\sqrt{12}+\sqrt{18}\longrightarrow$ factor the perfect squares out of 12 and 18 =$\sqrt{4\times3}+\sqrt{9\times2}\longrightarrow$ multiplication property of square roots =$(\sqrt4)(\sqrt3)+(\sqrt9)(\sqrt2)\longrightarrow$ simplify =$2\sqrt3+3\sqrt2$

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