Answer
$2\sqrt3+3\sqrt2$
Work Step by Step
$\sqrt6(\sqrt2+\sqrt3)\longrightarrow$ use the distributive property
=$(\sqrt6)(\sqrt2)+(\sqrt6)(\sqrt3)\longrightarrow$ multiplication property of square roots
=$\sqrt{12}+\sqrt{18}\longrightarrow$ factor the perfect squares out of 12 and 18
=$\sqrt{4\times3}+\sqrt{9\times2}\longrightarrow$ multiplication property of square roots
=$(\sqrt4)(\sqrt3)+(\sqrt9)(\sqrt2)\longrightarrow$ simplify
=$2\sqrt3+3\sqrt2$
