Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.2 - More on Trigonometric Equations - 6.2 Problem Set - Page 332: 27

Answer

$x=\{\frac{\pi}{4}\}$

Work Step by Step

$sin(x)+cos(x)=\sqrt{2}$ $(sin(x)+cos(x))^2=(\sqrt{2})^2\;\;\;\;\;\;\;\;\;\;$ $sin^2(x)+2sin(x)cos(x)+cos^2(x)=2\;\;\;\;\;\;\;\;\;\;\;\;$ $2sin(x)cos(x)+1=2$ $sin(2x)=1$ $2x= sin^{-1}(1)$ $2x=\frac{\pi}{2}\;\;\;\;\;\;\;\;\;\;\;\;\;\;$ Divided each side by $2$ $x=\frac{\pi}{4}$ $x=\{\frac{\pi}{4}\}$
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