Answer
$x=\{\frac{\pi}{4}\}$
Work Step by Step
$sin(x)+cos(x)=\sqrt{2}$
$(sin(x)+cos(x))^2=(\sqrt{2})^2\;\;\;\;\;\;\;\;\;\;$
$sin^2(x)+2sin(x)cos(x)+cos^2(x)=2\;\;\;\;\;\;\;\;\;\;\;\;$
$2sin(x)cos(x)+1=2$
$sin(2x)=1$
$2x= sin^{-1}(1)$
$2x=\frac{\pi}{2}\;\;\;\;\;\;\;\;\;\;\;\;\;\;$ Divided each side by $2$
$x=\frac{\pi}{4}$
$x=\{\frac{\pi}{4}\}$