Answer
$\dfrac{3+2i}{7}$
Work Step by Step
Using $i^2=-1$, the expression $
\dfrac{2-3i}{-7i}
$ simplifies to
\begin{array}{l}
\dfrac{2-3i}{-7i}
\cdot
\dfrac{i}{i}
\\\\=
\dfrac{2i-3i^2}{-7i^2}
\\\\=
\dfrac{2i-3(-1)}{-7(-1)}
\\\\=
\dfrac{3+2i}{7}
.\end{array}